Answer: -3 and -4
Step-by-step explanation:
If
is the first number in the progression, and
is the common ratio between consecutive terms, then the first four terms in the progression are

We want to have

In the second equation, we have

and in the first, we have

Substituting this into the second equation, we find

So now we have

Then the four numbers are

Answer:
(4, -8)
Step-by-step explanation:
The components of a vector are found by subtracting the tail from the head.
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Head - Tail = (1, -6) -(-3, 2) = (1 -(-3), -6 -2) = (4, -8)
⇒ The component form is (4, -8), or maybe 4<em>i</em> -8<em>j</em>.
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<em>Additional comment</em>
There are many ways that the components of vectors can be described. The particular format you are expected to use will likely be found in your curriculum materials.
2x2x5x5 or 2^2*5^5 hope this helps!