Question

What is the cube root of -729a^9b^6? -9a^3b^2 -9a^2b^ -8a^3b^2 -8a^2b^3

Answer 1

Answer:

$= 9a^3b^2$

Step-by-step explanation:

$\sqrt[3]{-729a^9b^6} =$

$= ((-9)^3a^9b^6)^{\frac{1}{3}$

$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$

$= (-9)^{1} \times a^{3} \times b^{2}$

$= -9a^3b^2$