Which is the better deal?

Mathematics

2 answers:

Reptile [31]3 years ago

7 0

Answer:

The better deal is 10 cans of soda for $5.50

Step-by-step explanation:

6 cans of soda for $3.60 means each can of soda is worth .60 cents
4 cans of soda for $2.36 means each can of soda is worth .59 cents
10 cans of soda for $5.50 means each can of soda is worth .55 cents

Therefore, 10 cans of soda for $5.50 is the best deal because you are getting the most cans of soda for the cheapest amount of money.

Hope this helped!

Alona [7]3 years ago

3 0

Answer:

10 cans for $5.50

Step-by-step explanation:

3.60/6= $0.60 per can

2.36/4= $0.59 per can

5.50/10= $0.55 per can

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What times 3 equals 3/10

Mumz [18]

Answer:

1/10

Step-by-step explanation:

Divide 3/10 by 3. Remember to "keep, flip, change".

3/10 ÷ 3/1

3/10 × 1/3

Multiply across: 3/10 × 1/3 = 3/30

Simplify: 3/30 = 1/10

7 0

3 years ago

What value is equivalent to 52 + 53 − 54? A) -475 B) -350 C) -125 D) 5

Dafna1 [17]

None of these answer choices are correct. The answer would be 51. 52+53=105

105-54=51

7 0

3 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$