Answer:
Option B is correct
the degree of rotation is, 
Step-by-step explanation:
A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.
To find the degree of rotation using a standard rotation matrix i.e,

Given the matrix: 
Now, equate the given matrix with standard matrix we have;
= 
On comparing we get;
and
As,we know:

we get;

and

we get;

Therefore, the degree of rotation is, 
Answer:
side of 6.124 ft and height of 3.674 ft
Step-by-step explanation:
Let's s be the side of the square base and h be the height of the rectangular box.
The base and the roof would have an area of
and cost of

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh
So the total cost for the material is



The volume of the shed has the following formula

To find the maximum value for V, we can take its first derivative, and set it to 0




h = 45/s - 0.6s = 3.674 ft
72=1,72,2,36,3,24,4,18,6,12,8,9
28=1,28,2,14,4,7
So,the answer is 4
Answer:
8 - (3 x 2) - (1 + 1) = 0
or
8 - 3 x 2 - (1 + 1) = 0
Remember PEMDAS.
If I put parenthesis around 3 x 2, I get 6.
But 8 - 6 = 2
How can we make 2 - 1 + 1 = 0?
If we look at PEMDAS, we know (2 - 1) + 1 = 2, but the answer needs to be 0.
So now try 2 - (1 + 1) and that gives me 0.
And it says parentheses...but you can also do 8 - 3 x 2 - (1 + 1) = 0.

I'm pretty sure this is right because there is 1.5 per one Wich is also written as a fraction