Question

Equation of the circle is x^2 +(y-10)^2=16. The radius of the circle is___units. The center of the circle is at ___

Answer 1

Answer:

Radius=4 units

Centre= (0,-10)

Step-by-step explanation:

Given equation of circle is x^2 +(y-10)^2=16

Comparing it with (x-h)^2 +(y-k)^2 = r^2 ,we get,

r=4

Since, centre of a circle=(h,k)=(0,-10)

Answer 2

Answer:

Center (0;10) Radius= 4. Make me brainliest? :(

Step-by-step explanation:

$(x + 0)^{2} + (y - 10)^{2} = 16 \\ center(0.10) \\ radius = \sqrt{16} = 4$