The moment M that will produce a maximum stress of 70 MPa on the cross-section of 177.3 will be 13.533 kN-m.
<h3>What is bending stress?</h3>
Bending stress is the typical stress that an item experiences when it is exposed to a heavy load at a specific spot, causing it to bent and fatigue.
The moment of inertia above the neutral axis will be
Iₓₓ = 99 x 84.7³/3 - (99 - 12 x 3) (84.7 - 12)³/3
Iₓₓ = 11983247 mm⁴
The moment of inertia below the neutral axis will be
Iₓₓ = 2 x 12 x (87 - 84.7)³/3 + 12 x 177.3³/3
Iₓₓ = 22294005 mm⁴
Then the moment of inertia about the neutral axis will be
Iₓₓ = + 11983247 + 22294005
Iₓₓ = 34277252 mm⁴
Then for maximum bending stress, we have
M = σ x Iₓₓ / y(max)
We have
σ = 70 MPa
Iₓₓ = 34277252 mm⁴
y(max) = 177.3
Then we have
M = 70 x 34277252 / 177.3
M = 13.533 kN-m
More about the bending stress link is given below.
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Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.
Step-by-step explanation:
The interquartile range are resistant to outliers and can be used for data having glaring outliers.
Outliers are values that are too far away from the central value.
Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.
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Step-by-step explanation:
4 + 2 x 7
6 x 7
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C
Step-by-step explanation:
