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3 years ago

60 POINTS PLEASE HELP FAST!!!! write the equation of a line in standard form that passes through the points (-4,-1) and (1.5,2)

1 answer:

5 0

You find your slope with the equation

(y2-y1)/(x2-x1)

(-1-2)/ -4-1.5)

(-3)/(-5.5)

.54x is your slope

you then plug that into your equation.

y=mx+b

y=.54x+b

you substitute one of our coordinates.

(-4,-1)

-1=.54(-4)+b

-1=-3.45+b

+3.45

2.45=b

your equation is

y=.54x+2.45

standard form

y-.54x=2.45

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3 years ago

3x + ky = 8

sattari [20]

Answer:

(a): x is 3 and ky is -1

(b): k is -2

Step-by-step explanation:

Let: 3x + ky = 8 be equation (a)

x - 2 ky = 5 be equation (b)

Then multiply equation (a) by 2:

→ 6x + 2ky = 16, let it be equation (c)

Then equation (c) + equation (b):

${ \sf{(6 + 1)x + (2 - 2)ky = (16 + 5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}$

Then ky :

${ \sf{2ky = 3 - 5}} \\ { \sf{ky = - 1}}$

${ \bf{y = \frac{1}{2} }} \\ { \sf{ky = - 1}} \\ { \sf{k = - 2}}$

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