Algebra 1 help please!
1 answer:
Answer:
and
Step-by-step explanation:
To solve this, you must set up a system of equations. The first sentence says that there are two numbers and that their sum is 91, so your first equation is . For the next equation, it says that the difference of those same numbers is 1, which means that the equation is
. Now, putting those two together for the system of equations, it's easiest to add them. The result will be
which when simplified gives you the value of x. Taking the value of x, you can substitute in the second equation to find the value of y.
Hope this helped!
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Answer:
- (x-4.5)^2 +(y +5)^2 = 30.25
- x = (1/8)y^2 +(1/2)y +(1/2)
- y^2/36 -x^2/64 = 1
- x^2/16 +y^2/25 = 1
Step-by-step explanation:
1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.
(x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15
(x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form
Important features: center = (4.5, -5); radius = 5.5.
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2. To put this in the form x=f(y), we need to add 8x, then divide by 8.
x = (1/8)y^2 +(1/2)y +(1/2)
Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.
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3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:
y^2/36 -x^2/64 = 1
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4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.
x^2/16 +b^2/25 = 1
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The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.
Answer:
a₁ = 6
Step-by-step explanation:
The sum to n terms of a geometric sequence is
=
where a₁ is the first term and r the common ratio
Here = 1530 and r = 2, thus
= 1530 , that is
a₁ (256 - 1) = 1530
255a₁ = 1530 ( divide both sides by 255 )
a₁ = 6