Question

Write the point slope form of an equation of the line through the points (-7,7) and (4,1)

Answer 1

• (-7,7)
• (4,1)

Slope:-

• m=1-7/4+7
• m=-6/11

Equation in point slope form

• y-7=-6/11(x+7)

Option A

Answer 2

Answer:

$\textsf{A)} \quad y-7=-\dfrac{6}{11}(x+7)$

Step-by-step explanation:

Step 1:  Find the slope

Define the points:

$\textsf{let}\:(x_1,y_1)=(-7,7)$

$\textsf{let}\:(x_2,y_2)=(4,1)$

Use the slope formula to find the slope:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-7}{4-(-7)}=-\dfrac{6}{11}$

Step 2:  Find the equation

Use the found slope from step 1 together with one of the given points in the point-slope form of a linear equation:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=-\dfrac{6}{11}(x-(-7))$

$\implies y-7=-\dfrac{6}{11}(x+7)$

Conclusion

Therefore, the equation of the line that passes through the points (-7, 7) and (4, 1) is:

$y-7=-\dfrac{6}{11}(x+7)$