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3 years ago

11

What is the value of x in the model below? Enter your answer in the box.

2 answers:

Blababa [14]3 years ago

8 0

$x+(-10)=-16\\\\x-10=-16\\\\x=-6$

sp2606 [1]3 years ago

3 0

It looks like the scale is balanced so that means you can set one side equal to the other which leaves you with the equation x+(-10)=-16

To get x by itself add x to each side to get x=-6

X=-6 is your answer

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Factor out the coefficient of the variable 5/6s+4/6

nirvana33 [79]

Okie, we find out the coefficient
5/6 s+ 4/6= 1/6 x 5s+ 1/6 x 4= 1/6(5s+4)

we have done this
Have a good day

5 0

2 years ago

The function h(t) = -16t2 + 48t + 28 models the height (in feet) of a ball where t is the time (in seconds).

Alex17521 [72]

Answer:

64

Step-by-step explanation:

<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have $h'(t) = -32t + 48$ , which equals zero when $t = 3/2 = 1.5$ . The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.

<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.

5 0

2 years ago

Can some one help me solve these 3 questions?

worty [1.4K]

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5 0

2 years ago

A boat attempts to sail due east at 15km/h, but is taken off course by a current of 5 km/h flowing in the southwest direction. F

SCORPION-xisa [38]

Answer:

Resultant speed = 12 km/h.

Bearing is 107.14 degrees.

Step-by-step explanation:

This can be represented by a triangle of velocities with lengths 15 and 5 with the included angle = 45 degrees.

To find the velocity of the resultant we use cosine rule:

v^2 = 15^2 + 5^2 - 2*5*15cos 45

v^2 = 143.934

v = 12.0 km/h to the nearest tenth.

To find the bearing we use the sine rule to find the angle down from due east>

12 / sin 45 = 5/ sin x

sin x = 5 sin 45 / 12 = 0.2946278

x = 17.14 degrees.

Bearing is therefore 90 + 17.14 = 107.14 degrees.

8 0

2 years ago

Find the coordinates of the point (x,y) at the given angle θ on a circle of radius r centered at the origin. Show all work. Roun

beks73 [17]

Answer:

(i) The equivalent coordinates in rectangular form are $(x, y) = (-3.277,-2.294)$ .

(ii) The equivalent coordinates in rectangular form are $(x, y) = (0.866, 0.5)$ .

Step-by-step explanation:

In this exercise we must find the equivalent coordinates in rectangular form from polar form. That is:

$(x, y) = (r\cdot \cos \theta, r\cdot \sin \theta)$

Where:

$r$ - Norm of vector, dimensionless.

$\theta$ - Direction of vector with respect to +x semiaxis, measured in sexagesimal degrees.

(i) ( $r = 4$ , $\theta = 215^{\circ}$ )

$(x. y) = (4\cdot \cos 215^{\circ}, 4\cdot \sin 215^{\circ})$

$(x, y) = (-3.277,-2.294)$

The equivalent coordinates in rectangular form are $(x, y) = (-3.277,-2.294)$ .

(ii) ( $r = 1$ , $\theta = 30^{\circ}$ )

$(x. y) = (1\cdot \cos 30^{\circ}, 1\cdot \sin 30^{\circ})$

$(x, y) = (0.866, 0.5)$

The equivalent coordinates in rectangular form are $(x, y) = (0.866, 0.5)$ .

6 0

2 years ago