Okie, we find out the coefficient
5/6 s+ 4/6= 1/6 x 5s+ 1/6 x 4= 1/6(5s+4)
we have done this
Have a good day
Answer:
64
Step-by-step explanation:
<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have
, which equals zero when
. The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.
<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.
Answer:
Resultant speed = 12 km/h.
Bearing is 107.14 degrees.
Step-by-step explanation:
This can be represented by a triangle of velocities with lengths 15 and 5 with the included angle = 45 degrees.
To find the velocity of the resultant we use cosine rule:
v^2 = 15^2 + 5^2 - 2*5*15cos 45
v^2 = 143.934
v = 12.0 km/h to the nearest tenth.
To find the bearing we use the sine rule to find the angle down from due east>
12 / sin 45 = 5/ sin x
sin x = 5 sin 45 / 12 = 0.2946278
x = 17.14 degrees.
Bearing is therefore 90 + 17.14 = 107.14 degrees.
Answer:
(i) The equivalent coordinates in rectangular form are
.
(ii) The equivalent coordinates in rectangular form are
.
Step-by-step explanation:
In this exercise we must find the equivalent coordinates in rectangular form from polar form. That is:

Where:
- Norm of vector, dimensionless.
- Direction of vector with respect to +x semiaxis, measured in sexagesimal degrees.
(i) (
,
)


The equivalent coordinates in rectangular form are
.
(ii) (
,
)


The equivalent coordinates in rectangular form are
.