Find 5 rational numbers between 1/3 & 2/5

Mathematics

1 answer:

Alexeev081 [22]3 years ago

3 0

Answer:

41/120, 7/20, 43/120, 11/30, 3/8

Step-by-step explanation:

Write the numbers.

1/3 & 2/5

We need a common denominator, but not the least common denominator. Both 3 and 5 are factors of 60, so let's use 60 as the common denominator.

Multiply 1/3 by 20/20:

1/3 = 20/60

Multiply 2/5 by 12/12:

2/5 = 24/60

Let's multiply each fraction again, but this time by 2/2.

1/3 = 40/120

2/5 = 48/120

Now it's easy to find 5 numbers between 40 and 48, so we get:

41/120, 42/120, 43/120, 44/120, 45/120

Some of these fractions can be reduced, so our answer is:

41/120, 7/20, 43/120, 11/30, 3/8

You might be interested in

Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

torisob [31]

Fermat's little theorem states that
$a^p$ ≡a mod p

If we divide both sides by a, then
$a^{p-1}$ ≡1 mod p
=>
$a^{17-1}$ ≡1 mod 17
$a^{16}$ ≡1 mod 17

Rewrite
$a^{1000000}$ mod 17 as
$=(a^{16})^{62500}$ mod 17
and apply Fermat's little theorem
$=(1)^{62500}$ mod 17
=>
$=(1)$ mod 17

So we conclude that
$a^{1000000}$ ≡1 mod 17

6 0

3 years ago

Solve for x in the inequality below. 4x-8<5x+4

Eddi Din [679]

Answer:

Step-by-step explanation:

4x-8<5x+4

4x<5x+12

-x<12

flip sign

x > -12

3 0