I am pretty sure R is -19 meters and N is -7 and A is 476 AD
(x-3)(x+4). -3,4 multiply to -12, and add to get 1
There aren't really any instructions for this, so I'll just go ahead and find the total amount of money for both months. The first month Adriano had 200 subscribers. 5 times 200 is 1000, so Adriano received $1000 that month. The second month 40 members joined, but 10 cancelled their subscription. Taking this into account, we'll just say that 30 members joined. 30 times 5 is 150, and 150 plus 1000 is 1150. Therefore, Adriano had to have received $1150 the second month.
I'm not entirely sure what the question was to begin with, but I hope this answers it!
Answer:
The percentage of the bank's customers carry daily balances between $700 and $1,000 is 65.7%.
The minimum daily balance on which it should be willing to pay interest is $1,198.
Step-by-step explanation:
We have a normal distribution with mean = $800 and standard deviation = $150.
a) We can calculate this value with the standard normal distribution, calculating the z-value for $700 and $1,000.

The percentage of the bank's customers carry daily balances between $700 and $1,000 is 65.7%.
b) We must calculate from what amount only 6% of the accounts remain.
This is done by solving:

This happens for a z-value of z=2.652.
This corresponds to a amount of $1,198.

The minimum daily balance on which it should be willing to pay interest is $1,198.