The value of the car is January 2003 is $199,148.54.
<h3>What is the value of the car?</h3>
Depreciation is the rate of decline in the value of an asset with the passage of time.
The exponential equation that can be used to determine the value of the car is:
Value of the car = purchase value(1 - rate of decline)^time
400,000 x (1 - 0.16)^(2003 - 1999)
400,000 x (0.84^4) = $199,148.54
To learn more about depreciation, please check: brainly.com/question/15085226
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Hey there!
We may ask. What exactly is a term anyways.
Well, a term is a single number, a variable, or a number and a variable that would have to be multiply together. This is what a term would be.
Therefore, as we look above, we see the following equation.
9a+4b-18
18 is a term
4b is a term
9a is a term
This whole thing, would be called an expression, as this is expression something. Perhaps the amount of students who ate ice-cream at a football game, or something similar.
I hope you found this helpful! :)
You need to use the distance formula
![d = \sqrt{ {(x - x)}^{2} + {(y - y)}^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%20%7B%28x%20-%20x%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%28y%20-%20y%29%7D%5E%7B2%7D%20%7D%20)
![\sqrt{ {(5 + 3)}^{2} + {( - 2 - 8)}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7B%285%20%2B%203%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%28%20-%202%20-%208%29%7D%5E%7B2%7D%20%7D%20)
so the distance between points (5,-2) and (-3,8) is
![2 \sqrt{41}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B41%7D%20)
which won't simplify so it stays as is
Answer:
its not 80k/3000 someone answer
Step-by-step explanation:
What is ur subject i would lov o help