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Komok [63]
2 years ago
6

225 729 25 144 응 16 81

Mathematics
1 answer:
k0ka [10]2 years ago
4 0

Answer: 5/16

Step-by-step explanation:

For this question, note that:

\sqrt{16}=4\\ \\ \sqrt{25}=5 \\\\\sqrt{81}=9\\\\\sqrt{144}=12\\\\\sqrt{225}=15\\\\\sqrt{729}=27

This means we can rewrite the given expression as:

\left(\frac{15}{27}-\frac{5}{12} \right) \div \frac{4}{9}\\\\=\left(\frac{5}{9}-\frac{5}{12} \right) \div \frac{4}{9}\\\\=\left(\frac{(5)(12)-(5)(9)}{(9)(12)} \right) \div \frac{4}{9}\\\\=\frac{15}{108} \div \frac{4}{9}\\\\=\frac{5}{36} \div \frac{4}{9}\\\\=\frac{5}{36} \times \frac{9}{4}\\\\=\frac{45}{144}\\\\=\boxed{\frac{5}{16}}

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Answer:

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Step-by-step explanation:

The sum of the 3 interior angles of a triangle = 180°, hence

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3 years ago
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3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

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There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
Find the amplitude and period of y = 5 cos (4x)
dezoksy [38]

Answer: amplitude is 5 and Period is pi/2

Step-by-step explanation:

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