Solve the following √50 x 3√2

1 answer:

5 0

$\sqrt{50} \times 3\sqrt 2\\\\=\sqrt{25 \times 2} \times 3\sqrt 2\\\\=5\sqrt 2 \times 3\sqrt 2\\\\=15 \left(\sqrt 2 \right)^2\\\\=15 \times 2\\\\=30$

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suppose that $2,000 is loaned at a rate of 18.5% compounded semi-annually assume that no payments are made find the amount after

pogonyaev

Answer: 2000(1+0.185/2)to the power of 3/2

= $2283.82

Step-by-step explanation: compounded interest is A= P(1 +r) the to power of N

So assuming semi annually means twice a year

2000(1+0.185/2)to the power of 3/2

6 0

3 years ago

WILL MARK BRAINLIEST FOR THE BEST ANSWER. PLEASE SHOW FULL SOLUTIONS. THANK YOU AND GOD BLESS. THE QUESTION IS ATTACHED. :)

Anuta_ua [19.1K]

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Answer:

(x, y) = (34/5, -4/5) = (6.8, -0.8)

Step-by-step explanation:

Subtract the first equation from the second to eliminate x.

$\left(\dfrac{x}{3}-\dfrac{y}{2}\right)-\left(\dfrac{x-5}{3}+\dfrac{y+2}{3}\right)=\left(\dfrac{8}{3}\right)-(1)\\\\y\left(-\dfrac{1}{2}-\dfrac{1}{3}\right)+\left(\dfrac{5}{3}-\dfrac{2}{3}\right)=\dfrac{5}{3} \qquad\text{partially simplify}\\\\-\dfrac{5}{6}y=\dfrac{2}{3} \qquad\text{subtract 1}\\\\y=-\dfrac{4}{5} \qquad\text{multiply by $-\dfrac{6}{5}$}$

Substituting for y in the second equation, we can find x.

$\dfrac{x}{3}-\dfrac{1}{2}\left(-\dfrac{4}{5}\right)=\dfrac{8}{3}\\\\5x +6=40 \qquad\text{multiply by 15}\\\\5x=34\qquad\text{subtract 6}\\\\x=\dfrac{34}{5}$