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2 years ago

Find the values of a and b so that the equation below is an identity: (x+2)³-3(x² −2x) = x³ + ax² +bx+8

Mathematics

1 answer:

algol132 years ago

4 0

Answer: -10 and 31 respectively

Step-by-step explanation:

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3 years ago

Solve the equation. 2/3 - 4x 7/2= -9x+ 5/6 step by step

Lostsunrise [7]

Answer: $\bold{x=\dfrac{11}{21}}$

<u>Step-by-step explanation:</u>

$\dfrac{2}{3}-\dfrac{4x+7}{2}=-9x+\dfrac{5}{6}\\\\(6)\dfrac{2}{3}-(6)\dfrac{4x+7}{2}=-9x(6)+(6)\dfrac{5}{6}\qquad \text{(multiplied by LCD) }\\\\4 - 12x-21=-54x+5\qquad \text{(simplified)}\\\\-12x - 17 = -54x + 5\qquad \text{(added like terms)}\\\\42x-17=5\qquad \text{(added 54x to both sides)}\\\\42x = 22\qquad \text{(added 17 to both sides)}\\\\x=\dfrac{22}{42}\qquad \text{(divided both sides by 42)}\\\\x=\dfrac{11}{21}\qquad \text{(reduced the fraction)}$

NOTE: The sign between 4x and 7 is missing in the question you posted. I assumed it was 4x + 7 in order to solve the equation.

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3 years ago

Read 2 more answers

Find the values of a and b so that the equation below is an identity: (x+2)³-3(x² −2x) = x³ + ax² +bx+8​

Find the values of a and b so that the equation below is an identity: (x+2)³-3(x² −2x) = x³ + ax² +bx+8