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Tanzania [10]
2 years ago
9

Find the values of a and b so that the equation below is an identity: (x+2)³-3(x² −2x) = x³ + ax² +bx+8​

Mathematics
1 answer:
algol132 years ago
4 0

Answer: -10 and 31 respectively

Step-by-step explanation:

You might be interested in
What is the slope of y = −4x + 5?<br> i. 4 ii. 5 iii. − 4 iv. 4/5
FromTheMoon [43]

Answer: -4

Step-by-step explanation:

-4 is the slope since the slope formula says that y = mx + b

Where, m is the slope

Therefore in this case -4 is the slope

5 0
3 years ago
Y=4x and 3x+y=-21. Substitute
gizmo_the_mogwai [7]

value of x= -3 and value of y = -12

Solution set is (-3,-12)

Step-by-step explanation:

We need to solve the system of equations using substitution

The system of equations are:

y=4x\\3x+y=-21

Solving:

Let

y=4x\,\,eq(1)\\3x+y=-21\,\,eq(2)

Solving:

Putting value of y from equation 1 into equation 2

3x+y=-21\\3x+4x=-21\\7x=-21\\x=-21/7\\x=-3

So, value of x = -3

Now, putting value of x into equation 1 and find value of y

y=4x\\y=4(-3)\\y=-12

Value of y = -12

So, value of x= -3 and value of y = -12

Solution set is (-3,-12)

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

5 0
3 years ago
SOMEONE PLEASE HELP ME WITH THIS ILL GIVE YOU BRAINLY IF YOU GET IT RIGHT ALSO PLEASE EXPLAIN HOW YOU GOT THE ANSWER!!!!
Liula [17]

i think it's A (good luck lol)

8 0
3 years ago
2) a) What is special about the temperature 100 °C?
aliya0001 [1]

Answer:

Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. Absolute zero is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion. hope this helps you

3 0
3 years ago
The point A(-3, -2) is translated using T: (x,y) → (x + 5, y - 3). What is the distance from A to A'?
Degger [83]

Answer:

d=5.39 units

Step-by-step explanation:

Given A (-3, -2)  

T= (x+5, y-3)

T= (-3+5, -2-3)

T=(2,-5)

Applying the translation on;

A( -3,-2)

A' (-3+2, -2+ -5)

A'= (-1, -7)

Distance

d= \sqrt { X2-X1)^2 + (Y2-Y1)^2

A = (-3,-2)     and  A'(-1, -7)

d=√ (-1--3)² + (-7--2)²

d=√ (2)²+(-5)²

d=√4+25

d=√29

d=5.39 units

4 0
3 years ago
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