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n200080 [17]
2 years ago
6

Sarah, Fiona and David share £40 in a ratio 3:3:2. How much money does each person get?

Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0

Answer:

ratio:3:3:2

total of ratio=3+3+2=8

total money=40

sara gets 5x 3/8=15

eiona gets 5x 3/8+15

david gets=5x 2/8=10

Step-by-step explanation:

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Answer:

the answer would be c

Step-by-step explanation: Because the values inside of the parenthesis don't have the same variable, they cannot be combined. Using the 9 on the outside of the parenthesis you would multiply 9 by 3r, which gives you 27r, and 9 by -4 to create -36. The new equation would be 27r - 36, which is equivalent to the equation shown next to it.

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2 years ago
Consider a triangle formed by connecting the three points: (0 0 0), (1 0 0), (1 1 1). a. Find the vector which is perpendicular
Sidana [21]

Answer:

=k−j   or (0 -1 1)

Step-by-step explanation:

The Vector or Outer Product two vectors, say →x&→y, is  

denoted by →x×→y, is a perpendicular vector to the plane containing them.

The given pts. A (0 0 0), B (1 0 0), C (1 1 1) lie in a

plane ABC.

As suchType equation here., the vectors (→(AB ) )and (→AC ) are members, ∈ of the plane ABC

That is □(→(AB )×(→AC))  to the plane ABC

(→(AB ) )=(1-0,0-0,0-0)=(1,0,0)

(→(AC ) )=(1-0,1-0,1-0)=(1,1,1)

(→(AB )×(→AC=  (0i -j  k)

=k−j  

Which is in the positive Z direction

3 0
3 years ago
Is 3/9 a function of y Equals 6X
sdas [7]

Answer:

yes

Step-by-step explanation:

well plug it in: y=6x -> y=6(3/9) and solve, yes if theres a slope of 1

5 0
3 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
2 years ago
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