1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nina [5.8K]
2 years ago
8

Please show NEC article 310.10(H)

Engineering
1 answer:
Misha Larkins [42]2 years ago
8 0

Conductors in Parallel is covered in 310.10(H). Often when working with higher ampacities, we find it to be cumbersome and expensive to keep increasing the size of the wire and conduit. The solution is often to use multiple runs that are connected to a common location on each end. Notice in the 2011 edition of the code that much of this section is highlighted gray, indicating new or revised text. The change here was that the previous code stated that you were permitted to parallel conductors 1/0 AWG and larger; however, it didn’t specifically prohibit you from paralleling smaller conductors, which was the intent and the way it was enforced in all my years of enforcement. However, that’s not what the actual language said, and ambiguous language cancause enforcement issues; therefore, in the 2011 code it was made clear that you are only allowed to parallel conductors 1/0 AWG and larger.

You might be interested in
Which type of snap ring plier expands the snap ring for removal?
4vir4ik [10]

Answer:

c I think so haven't took engineering in ages

4 0
3 years ago
An elastic cable is to be designed for bungee jumping from a tower 130 ft high. The specifications call for the cable to be 85 f
azamat

Answer:

<em>a) The spring constant is 50 lb/ft</em>

<em>b) The man is 26.3 ft close to the ground.</em>

<em></em>

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = <em>50 lb/ft</em>

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft =<em> 26.3 ft</em>

3 0
3 years ago
A system consists initially of nA moles of gas A at pressure p and temperature T and nB moles of gas B separate from gas A but a
Volgvan

Answer:

A) б = - R ( nA In Ya - nB In Yb )

B) s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced

Explanation:

A) assuming ideal gas behavior the expression for entropy produced

for a closed system : s2 - s1 = б

where : s1 ( initial entropy ) = nA sA ( T, P ) + nB sB ( T, P )

s2 ( final entropy ) = nA sA ( T, YaP ) + nB sB ( T, YbP )

∴ б = - R ( nA In Ya - nB In Yb )

B) Given that

Ya and Yb are less than 1  respectively, hence the value of б  = positive

also assuming the gases are identical

s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced when same gas at same temperature and same pressure are mixed

5 0
3 years ago
(a) A criterion is required for selecting a material with the lowest cost in a strength-limited design for a cylindrical tie rod
valentinak56 [21]

Answer:

For uniaxial tension the objective is to minimize cost:

C = mCm= ALrCm where m is mass, A is the cross-section area, r is density, and Cm is cost per unit mass. For strength limited design: F/A ≤sy, and A ≥ F/sy To minimize C = (F/sy) LrCm= (FL)(rCm/sy), minimize the quantity (rCm/sy). Maximize the material index,M =sy/(rCm)

b. The objective is to minimize cost C = mCm= b2LrCm, where A = b2 is the cross-section for strength limited design. It is necessary to eliminate the variable b from the equation.

Now if A= b2

Then b=A/2

Therefore cost C= mCm=A/2.2LrCm

= ALrCm

5 0
3 years ago
Read 2 more answers
Which phase of DevSecOps emphasizes reliability, performance, and scaling
rosijanka [135]

Answer:

"Test Phase " is the correct choice.

Explanation:

  • DevSecOps seems to be a community as well as experience of corporate data science which encompasses software design, regulation, including operational activities. This same main feature of DevSecOps has always been to strengthen customer achievement as well as expedition importance by computerizing, supervising as well as implementing data protection at all stages of the development including its development tools.
  • The testing method throughout the test phase would then help make sure that the controller is designed mostly under the responsibilities forecasted. The test focuses on either the reaction times, dependability, use of resources but instead interoperability of applications.
4 0
4 years ago
Other questions:
  • A large retail organization previously divided work among its four employee benefits staff into distinct specializations. One pe
    13·1 answer
  • A sample of wastewater is diluted 10 times. The diluted solution has an ultimate biochemical oxygen demand (BOD), Lo, of 30 mg/L
    9·1 answer
  • Brainly and points if you want
    13·2 answers
  • Forcing a solid piece of heated aluminum through a die forms:
    15·2 answers
  • Create a series of eight successive displacements that would program a robot to move in an octagonal path that is as close as yo
    8·1 answer
  • What are typical uses of Mainframe computer?​
    14·1 answer
  • Why do the legs of a head frame always slope towards the winch​
    12·1 answer
  • A service station has 10 employees who are responsible for checking in customers who bring their cars in to be serviced. The emp
    14·1 answer
  • What plane is this? and when was it made?
    11·1 answer
  • Technology is the study of the designed world. It is used primarily to __________. *
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!