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arsen [322]
3 years ago
13

Brainly and points if you want

Engineering
2 answers:
Tju [1.3M]3 years ago
8 0

Answer:

thank you

Explanation:

have a nice day

sertanlavr [38]3 years ago
6 0

Answer:

thankd

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A simple non-ideal Rankine cycle with water as the working fluid operates between the pressure limits of 15 MPa in the boiler an
konstantin123 [22]

Answer:

The right solution is "28.45%".

Explanation:

The given values are:

P_4=50\ kPa

h_4=0.7(2304.7)+340.5

    =1953.83 \ KJ/Kg

and,

P_3=15 \ mPa

h_3=hg

    =2610.8 \ KJ/Kg

s_3=sg

    =5.3108 \ KJ/Kgh

At 45,

⇒ x_{45} = \frac{5.3108-1.0912}{6.5019}

          =0.66

At P_4=50 \ Kpa,

h_f=340.54

or,

V_f=0.001030 \ m^3/Kg

then,

⇒ h_2=340.54+0.001030(15\times 10^{3}-50)

        =355.94 \ kJ/kg

hence,

The isentropic efficiency of turbine will be:

⇒ n_T=\frac{h_3-h_4}{h_3-h_{45}}

         =\frac{2610.8-1953.83}{2610.8-1836.26}

         =84.818 (%)

The thermal efficiency of cycle will be:

⇒ n_C=\frac{W_T-W_P}{2_{in}}

         =\frac{(2610.8-1953-83)-(355.93-340.54)}{2610.8-355.93}

         =28.45 (%)  

4 0
3 years ago
What minimum radius of curvature may be designed for safe operation of vehicles at 70 mi/hr if the maximum rate of superelevatio
aleksandr82 [10.1K]
Tell me why i got this question got it right and now won’t remember but i’ll get back at you when i remember
5 0
3 years ago
Identify the unit of the electrical parameters represented by L and C and prove that the resonant frequency (fr)=1÷2π√LC
Gre4nikov [31]

Answer:

L = Henry

C = Farad

Explanation:

The electrical parameter represented as L is the inductance whose unit is Henry(H).

The electrical parameter represented as C is the inductance whose unit is Farad

Resonance frequency occurs when the applied period force is equal to the natural frequency of the system upon which the force acts :

To obtain :

At resonance, Inductive reactance = capacitive reactance

Equate the inductive and capacitive reactance

Inductive reactance(Xl) = 2πFL

Capacitive Reactance(Xc) = 1/2πFC

Inductive reactance(Xl) = Capacitive Reactance(Xc)

2πFL = 1/2πFC

Multiplying both sides by F

F * 2πFL = F * 1/2πFC

2πF²L = 1/2πC

Isolating F²

F² = 1/2πC2πL

F² = 1/4π²LC

Take the square root of both sides to make F the subject

F = √1 / √4π²LC

F = 1 /2π√LC

Hence, the proof.

8 0
3 years ago
Cooling water for a chemical plant must be pumped from a river 2500 ft from the plant site. Preliminary design cans for a flow o
Vesna [10]

Answer:

The power cost savings for the 8 inches pipe offsets the increased cost for the pipe therefore to save costs the 8-inch pipe should be used

Explanation:

The given parameters in the question are;

The distance of the river from the the site, d = 2,500 ft.

The planned flow rate = 600 gal/min

The diameter of the pipe, d = 6-in.

The pipe material = Steel

The cost of pumping = 3 cents per kilowatt-hour

The Bernoulli's equation is presented as follows;

\dfrac{P_a}{\rho} + g\cdot Z_a + \dfrac{V^2_a}{2} + \eta\cdot W_p = \dfrac{P_b}{\rho} + g\cdot Z_b + \dfrac{V^2_b}{2} +h_f +W_m

{P_a} = {P_b} = Atmospheric \ pressure

Z_a  =  Z_b

Vₐ - 0 m/s (The river is taken as an infinite source)

W_m = 0

The head loss in 6 inches steel pipe of at flow rate of 600 gal/min = 1.19 psi/100 ft

Therefore; h_f = 1.19 × 2500/100 = 29.75 psi

\eta\cdot W_p = \dfrac{V^2_b}{2} +h_f

V_b = Q/A_b = 600 gal/min/(π·(6 in.)²/4) = 6.80829479 ft./s

V_b ≈ 6.81 ft./s

The pressure of the pump = P =  62.4 lb/ft³× (6.81 ft./s)²/2 + 29.75 psi ≈ 30.06 psi

The power of the pump = Q·P ≈ 30.06 psi × 600 gal/min = 7,845.50835 W

The power consumed per hour = 7,845.50835  × 60  × 60 W

The cost = 28,243.8301 kW × 3  = $847.31  per hour

Annual cost =  $847.31 × 8766 = $7,427,519.46

Pipe  cost = $15/ft × 2,500 ft = $37,500

Annual charges = 20% × Installed cost = 0.2 × $37,500 = $7,500

Total cost = $37,500 + $7,500 + $7,427,519.46 = $7,475,519.46

For the 8-in pipe, we have;

V_b = Q/A_b = 600 gal/min/(π·(8 in.)²/4) = 3.83 ft./s

h_f = 1.17 ft/100 feet

Total head loss = (2,500 ft/100 ft) × 1.17 ft. = 29.25 ft.

h_p = \dfrac{V^2_b}{2 \cdot g} +h_f

∴ h_p = (3.83 ft./s)²/(2 × 32.1740 ft/s²) + 29.25 ft. ≈ 29.5 ft.

The power of the pump = ρ·g·h × Q

Power of pump = 62.4 lb/ft³ × 32.1740 ft/s² × 29.5 ft.× 600 gal/min = 3,363.8047 W

The cost power consumed per annum = 3,363.8047 W × 60 × 60 × 3 × 8766 = $3,184,608.1

The Cost of the pipe = $20/ft × 2,500 ft. = $50,000

The total cost plus charges = $3,184,608.1 + $50,000 + $10,000 = $3,244,608.1

Therefore it is more affordable to use the 8-in pipe which provides substantial savings in power costs

8 0
3 years ago
A 65-tooth spur gear is in mesh with a 32-tooth pinion. For a diametral pitch equal to 7 and pressure angle equal to 20 degrees.
alex41 [277]

Answer:

0.4488 mm

Explanation:

Number of teeth in spur gear = 65

Number of teeth in pinion = 32

Diametral pitch = 7 = P

pressure angle = ∅ = 20°

Circular pitch of measured on the pitch circle is defined as the distance between two corresponding points.

Circular pitch

p=\frac{\pi}{P}\\\Rightarrow p=\frac{\pi}{7}\\\Rightarrow p=0.4488\ mm

So, the circular pitch is 0.4488 mm

6 0
3 years ago
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