Answer:
The pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting
Explanation:
since the same components are being casted at other foundries and they don't have the defects ,
Hence the reason for the defects experienced by these components can be caused when the pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting .
Answer:
def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):
for value in user_values:
if value < upper_threshold:
print(value)
def get_user_values():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
return lst
if __name__ == '__main__':
userValues = get_user_values()
upperThreshold = int(input())
output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)
Answer:
Answer is c. 2
Explanation:
Since friction is present at the contact between 2 materials thus coefficient of friction always involve 2 materials
Answer / Explanation:
Eavesdropping attack is also sometimes refereed to as sniffing attack. It is simply the process by which an attacker or hacker tries to penetrate very suddenly into an unaware individuals network or server with the intention to steal information transmitted over the network or server through that computer.
To prevent such attack, there are several mean which include installing network monitoring software to check who else is connected to the network but the most common method of preventing such attack is to encrypt the Hypertext Transfer Protocol (http) and the way to do this is by securing it with a sort of security key.
On installing the security key, the network becomes encrypted and secured such that whatever network transmitted over the network becomes encrypted and unable to read. The protocol then converts to (https).
Answer:
v = 1.076 m /s
Explanation:
Initial volume of balloon = 4/3 x 3.14 x (9.905/2)³
=508.56 m³
Final volume of balloon = 4/3 x 3.14 x (16.502/2)³
= 2351.73 m³
Increase in volume = 1843.17 m³
Cross sectional area of inlet A = 3.14 x( 1.458/2)²
A = 1.6687 m²
Volume rate of flow of air = cross sectional area x velocity of inflow
= 1 .6687 V [ V is velocity of inflow ]
Total time taken = Increase in volume / rate of flow of air
17.108 X 60 = 1843.17 / 1.6687 V
V =
v = 1.076 m /s