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2 years ago

Drag each expression to the correct location on the table.

Mathematics

1 answer:

Serjik [45]2 years ago

7 0

The simplified value is shown below:

<h3>What is exponents and powers?</h3>

Exponent refers to the number of times a number is used in a multiplication. Power can be defined as a number being multiplied by itself a specific number of times.

First,

3²*4³* $2^{-1}$ /(3*4)²

=9*64/144*2

= 576/288

Second,

(3*2)^4 * $3^{-3}$ /2³*3

=1296/8*81

=1296/648

Third,

$3^{-3} *2^{-3} *6^{3} /(4^{0} )^{2}$

= $6^{3} /(1 )^{2} *3^{3} *2^{3}$

= $2^{3}* 3^{3} /(1 )^{2} *3^{3} *2^{3}$

Fourth,

$2^{4}* 3^{5} /(2*3)^{5}\\=2^{4}* 3^{5} /2^{5}*3^{5}$

= 1/2

Learn more about exponents and powers here:

brainly.com/question/15722035

#SPJ1

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. A binary string containing M 0’s and N 1’s (in arbitrary order, where all orderings are equally likely) is sent over a network

Sophie [7]

Answer:

$P(k) = \frac{\binom{N}{k} \binom{(M+N) - N}{r-k}}{\binom{M+N}{r}}$

Step-by-step explanation:

We can model the string as a hypergeometric distribution, as each bit has two possible values, 1 or 0, and the chance of a 1 or 0 changes with every bit, as there are a finite number M of 0's and N of 1's and every bit takes one of those values.

If M+N (total size of the string) >> r (number of trials), we could model it as a binomial distribution as the probability of a 1 or 0 wouldn't change in a significant amount with every bit, but as we don't know the magnitude of M+N and r, we follow up with hypergeometric distribution.

The distribution has the following formula for probability:

$P(k) = \frac{\binom{K}{k} \binom{N - K}{n-k}}{\binom{N}{n}}$

Where k is the number of sucesses, K is how many total sucess states are in the population, N is the population size and n is the number of draws.

For our case, a 1 would be a sucess, i.e. k the number of 1's we want to know the probability, N our total number of 1's, M+N the length of the string (population size) and we want to analyse what happens in the first r bits (number of draws):

$P(k) = \frac{\binom{N}{k} \binom{(M+N) - N}{r-k}}{\binom{M+N}{r}}$

8 0

3 years ago

To factor 8x^2 + bx + 3, a student correctly rewrites the trinomial 8x^2 + px + qx + 3. What is the value of pq?

sergeinik [125]

Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).

answer: (-oo;0.5b²)

8 0

4 years ago

An article presents a study of health outcomes in women with symptoms of heart disease. In a sample of 115 women whose test resu

My name is Ann [436]

Answer:

z(s) is in the rejection region we reject H₀ μ₁ = μ₂ and support the claim that at CI 95 % the means of the two groups differs

Step-by-step explanation:

Sample 1:

Sise sample n₁ = 115

μ₁ = 169,9 mmHg

σ₁ = 24,8 mmHg

Sample 2:

Sise sample n₂ = 235

μ₂ = 163,3 mmHg

σ₂ = 25,8 mmHg

We can develop a test hypothesis for differences in means to investigate if the mean peak systolic blood pressure differs between these two groups

We will choose CI = 95 % then significance level α = 5 %

α = 0,05 α/2 = 0,025

z(c) for 0,025 is from z-table z(c) = 1,96

Test Hypothesis:

Null Hypothesis H₀ μ₁ = μ₂

Alternative Hypothesis Hₐ μ₁ ≠ μ₂

The alternative hypothesis tells us that the test is a two-tail test.

z(s) = ( μ₁ - μ₂ ) / √ σ₁²/n₁ + σ₂²/n₂

z(s) = ( 169,9 -163,3 ) / √ (24,8)² /115 + ( 25,8)²/235

z(s) = 6,6 / √5,35 + 2,83

z(s) = 6,6 / 2,86

z(s) = 2,30

Comparing |z(c)| and |z(s)|

z(s) > z(c)

z(s) is in the rejection region we reject H₀ μ₁ = μ₂ and support the claim that at CI 95 % the means of the two groups differs

6 0

3 years ago

Help me outttt !!!!!!!

baherus [9]

Answer:

its 3rd choice lol

Step-by-step explanation:

8 0

3 years ago

Account A and Account B both have a principal of $2,000 and an annual interest rate of 2%. No additional deposits or withdrawals

GuDViN [60]

Answer:

Account B earns more interest.

After 20 years, account B will have earned $171.89 more.

Step-by-step explanation:

Let's calculate the total for each account.

Account A:

Account A earns simple interest. We know that the principal value is $2000 and the interest rate is 2% or 0.02. We can use the simple interest formula:

$A=P(1+rt)$

Where A is the future value, P is the principal, r is the rate, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, and 20 for t. This yields:

$A=2000(1+0.02(20))$

Multiply and add:

$A=2000(1+0.4)=2000(1.4)$

Multiply. So, the total amount of money in Account A after 20 years is:

$A=\$2800$

Since we initially deposited $2000 and our total is now $2800, this means that we earned an interest of $2800-2000=\$ 800$

Account B:

Account B earns compound interest. Like Account A, Account B has a principal value of $2000 and the interest rate is 2% or 0.02. We also know that it's compounded annually, so once per year. We can use the compound interest formula:

$B=P(1+\frac{r}{n}})^{nt}$

Where B is the future value, P is the principal, r is the rate, n is the times compounded per year, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, n for 1 (since it's compounded annually), and t for 20. This yields:

$B=2000(1+\frac{0.02}{1})^{(1)(20)}$

Simplify this to acquire:

$B=2000(1.02)^{20}$

Evaluate. Use a calculator. So, after 20 years, the amount of money in Account B is:

$B\approx\$2971.89$

Since our principal was $2000, this means that we earned an interest of approximately $2971.89-2000=\$ 971.89$ .

So, Account A earned an interest of $800 and Account B earned an approximate interest of $971.89.

So, Account B earned more interest.

And it earned $971.89-800=\$ 171.89$ more than Account A.

And we're done!

5 0

3 years ago