Answer:
p = 0.38, n = 20
The probability that he throws more than 10 strikes = 0.09233
Step-by-step explanation:
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of times Jack wants to bowl = 20
x = Number of successes required = number of strikes he intends to get
p = probability of success = probability that Jack throws a strike = 0.38
q = probability of failure = probability that Jack doesn't throw a strike = 0.62
P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)
P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)
P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)
P(X > 10) = 0.09233
There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.
Answer:
y =x^2 +8x +15
factories form
y =( x+5 )( x+3 )
x intercept where the graph meet the x axis
y = x^2 +8x +15
let y =0
0 = x^2 +8x +15
0 = ( x + 5) (x+3)
o = x+5 or 0 = x+3
-5 = x or x = - 3
x intercept
(-5;0)
(-3 ;0)
axis of symmetry : where you will cut the graph into two half
x = - b/2a
x = - 8/2(1)
x = - 8/2
x = - 4
Domain
XER
Range
y > -1
Answer:
16 3 goes into 48 16 times.
Step-by-step explanation:
48÷3 = 16 3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3=48
Answer:
there is an infinet amount of answers.
Step-by-step explanation:
Answer: I think 13
Step-by-step explanation:
