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nika2105 [10]
2 years ago
15

Which operations is the following set closed under? Explain your answer. \(\left\{2,4,6,...\right\}\)

Mathematics
1 answer:
babymother [125]2 years ago
5 0

The operation that is being used to complete the sequence is an addition, in which each number is added + 2.

<h3>What is a sequence?</h3>

A sequence is a mathematical term that refers to the succession of numbers or other mathematical objects related to each other, which is characterized by taking into account the relative position of each number with respect to the previous one.

According to the above, it can be inferred that from the following sequence:

  • 2, 4, 6, ...

The operation that is defining the sequence is:

  • x + 2
  • 0 + 2 = 2
  • 2 + 2 = 4
  • 4 + 2 = 6

Learn more about sequences in: brainly.com/question/21961097

#SPJ1

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The value of a would be 4.2, because the negatives cancel out each other.
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A teacher corrected 8 math quizzes in 16 minutes.
Makovka662 [10]

Answer: 32

Step-by-step explanation:

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The surface area of a cube is 560,000 square centimeters. How many square meters is this?
tresset_1 [31]

Answer:

5,600 m^2

Step-by-step explanation:

a 1cm= 0.01m

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3 0
2 years ago
Read 2 more answers
The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

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2 years ago
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arlik [135]

Answer:

2

Step-by-step explanation:

1+1=2 so the answer is 2

5 0
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