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slavikrds [6]
2 years ago
13

Explain how the graph of y=|x+1|-2 will differ from the graph of y=|x|.

Mathematics
1 answer:
Natali5045456 [20]2 years ago
3 0

\bf ~~~~~~~~~~~~\textit{function transformations}\\\\\\f(x)=  A(  Bx+  C)+  D\\\\~~~~y=  A(  Bx+  C)+  D\\\\f(x)=  A\sqrt{  Bx+  C}+  D\\\\f(x)=  A(\mathbb{R})^{  Bx+  C}+  D\\\\f(x)=  A sin\left( B x+  C  \right)+  D\\\\--------------------\\\\\bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\\bullet \textit{ flips it upside-down if }  A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis}\\\\\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\~~~~~~\textit{reflection over the y-axis}\\\\\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\\bullet \textit{ vertical shift by }  D\\~~~~~~if\   D\textit{ is negative, downwards}\\\\~~~~~~if\   D\textit{ is positive, upwards}\\\\\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind,

\bf y=\stackrel{A}{1}|\stackrel{B}{1}x\stackrel{C}{+1}|\stackrel{D}{-2}

so is really just |x| but shifted some,

C/B = 1/1 = +1, horizontally to the right by 1 unit.

D = -2, vertically downwards by 2 units.

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What is 38/4 as a mixed number
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The answer is 9 1/2
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You flip a coin three times. What is the probability that you get heads all three times? Answer as a simplified fraction use the
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The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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4-(11/3)/4-(2/3)<br> how do i solve this
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Answer: 0.1 or \frac{1}{10}

Step-by-step explanation:

\frac{4-\frac{11}{3} }{4-\frac{2}{3} }

= \frac{1}{10}

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