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lesya [120]
2 years ago
7

Construct one table that includes relative frequencies based on the frequency distributions shown​ below, then compare the amoun

ts of tar in nonfiltered and filtered cigarettes. Do the cigarette filters appear to be​ effective? (Hint: The filters reduce the amount of tar ingested by the​ smoker.)
Mathematics
1 answer:
andreev551 [17]2 years ago
6 0

Based on the relative frequency table that compares nonfiltered and filtered cigarettes, we can infer that cigarette filters are effective because they reduce larger tar amounts.

<h3>How can the relative frequency table be drawn?</h3>

Tar (mg)                     Relative Frequency            Relative Frequency  

                                        (nonfiltered)                              (filtered)

6 - 11                                 0/ 25 = 0%                             1 / 25 = 4%

12 - 17                                0/ 25 = 0%                             1 / 25 = 4%

18 - 23                                2/ 25 = 8%                            5 / 25 = 20%

24 - 29                              1/ 25 = 4%                             18 / 25 = 72%

30 - 35                               13/ 25 = 52%                          0 / 25 = 0%

36 - 41                               6/ 25 = 24%                         0 / 25 = 0%

42 - 47                              3 / 25 = 12%                         0 / 25 = 0%

Total                                 25 / 25 = 100%                     25 / 25 = 100%

From the table, we can see that the unfiltered cigarette has higher tar amounts which means that cigarette filters are effective in reducing tar content.

Find out more on relative frequency at brainly.com/question/1094036.

#SPJ1

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