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RSB [31]
3 years ago
6

With Big Phone Company, you pay $0.39 for the connection and $0.03 per minute

Mathematics
1 answer:
TEA [102]3 years ago
3 0
The answer us D i think
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What do you predict the solution for the system 5x-6y=7 and 6x-7y=8 will be ?<br>​
Alenkinab [10]
System of Linear Equations entered :

[1] 5x - 6y = 7
[2] 6x - 7y = 8
Graphic Representation of the Equations :

-6y + 5x = 7 -7y + 6x = 8

Solve equation [2] for the variable x


[2] 6x = 7y + 8

[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]

[1] 5•(7y/6+4/3) - 6y = 7
[1] - y/6 = 1/3
[1] - y = 2
// Solve equation [1] for the variable y


[1] y = - 2
// By now we know this much :

x = 7y/6+4/3
y = -2
// Use the y value to solve for x

x = (7/6)(-2)+4/3 = -1
8 0
3 years ago
A number between 49 and 95 that is a multiple of 4,5, and 10?
jek_recluse [69]

Answer: 60 and 80

Step-by-step explanation: Start off with the highest number, which is 10. The numbers between 49 and 95 that can be divided by 10 are 50, 60, 70, 80, and 90. Next, figure out what can be divided by 5. All of them can. Next, find out what numbers can be divided by 4. 50, 70, and 90 can’t because they would end up as a decimals. 60 and 80 can be divided by 4, 5, and 10.

5 0
3 years ago
Kris is 2 meters tall and casts a shadow
postnew [5]

The tree is 20 m tall .

Step-by-step explanation:

<h2>Given : </h2>
  • 2m tall tree cast a shadow 4 m long .

=> 2 m tree = 4 m long

If we find shadow of 1 m tall tree = 4/2

=> we have to find height of 10 m tall tree which is .. = 4/2 × 10 = > 20 m

6 0
2 years ago
Show that any number of the form ABCABC (e.g. 356356) is divisible by 13.
Shtirlitz [24]

We could write such a number as

10^5a+10^4b+10^3c+10^2a+10b+c

=10^2(10^3+1)a+10(10^3+1)b+(10^3+1)c

=(10^3+1)(100a+10b+c)

10^3+1=1001=13\cdot77 so we're done.

8 0
3 years ago
Graph the line with the equation y<br> - 1x – 7.
Vladimir79 [104]

Hey there!

Answer:\boxed{\text{Slope:}-1}\boxed{\text{y-intercept:}(0,-7)}

Graph coming up right below!

Hope this helps!

\text{-TestedHyperr}

8 0
3 years ago
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