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Georgia [21]
2 years ago
12

Please help! Giving brainlist!

Mathematics
2 answers:
Sauron [17]2 years ago
8 0

Answer:

  ∠AXB or ∠PXQ or ∠AXQ or ∠PXB or ...

Step-by-step explanation:

A vertical angle is formed from the rays that are opposite the rays that form the original angle.

__

<h3>opposite rays</h3>

The rays forming angle CXD are rays XC and XD. The ray opposite XC will have end point X, and can be named by either of the two points shown on the ray: A or P. That is, rays XA and XP are opposite ray XC.

Similarly, rays XB and XQ are opposite ray XD.

<h3>vertical angle</h3>

The vertical angle can be named using either of the first pair of opposite rays with either of the second pair:

  ∠AXB, ∠PXB, ∠AXQ, ∠PXQ

Of course, the ray names can be reversed in the angle names:

  ∠BXA, ∠BXP, ∠QXA, ∠QXP

Altogether, there are 8 ways to name the vertical angle to ∠CXD.

aalyn [17]2 years ago
3 0
The angle that is vertical (opposite) with ∠CXD = ∠AXB
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xxTIMURxx [149]

Answer: $249,300

Step-by-step explanation:

The exact formula would be if I think this is right

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3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

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we know that

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mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

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we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

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Step-by-step explanation:

I hoped it helped!!!

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