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tankabanditka [31]
2 years ago
6

Which pyramid has a greater volume, and how much greater is its volume? A rectangular pyramid on the left with a base of 7 inche

s by 6 inches and height of 3 inches. A rectangular pyramid on the right with a base of 4 inches by 3 inches and a height of 10 inches. The volume of the pyramid on the left is greater by 2 inches cubed. The volume of the pyramid on the left is greater by 6 inches cubed. The volume of the pyramid on the right is greater by 2 inches cubed. The volume of the pyramid on the right is greater by 6 inches cubed
Mathematics
1 answer:
Nonamiya [84]2 years ago
3 0

The volume of the pyramid on the left is greater by 8 inches cubed

We have given that,

A rectangular pyramid on the left with a base of 7 inches by 6 inches and a height of 3 inches.

A rectangular pyramid on the right with a base of 4 inches by 3 inches and a height of 10 inches.

The volume of the pyramid on the left is greater by 2 inches cubed. The volume of the pyramid on the left is greater by 6 inches cubed.

The equation for finding the volume of a pyramid is,

<h3>What is the volume of a pyramid?</h3>

lwh/3

when you input the values of the two pyramids into this equation you get the left pyramid having a volume of 128 inches cubed and the right pyramid having a volume of 120 inches cubed.

Therefore, 128 - 120 = 8

To learn more about the pyramid visit:

brainly.com/question/218706

#SPJ1

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Elena-2011 [213]

surface area (S) of a right rectangular solid is:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

W = width

H = height

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you have:

L = 7

W = a

H = 4

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formula becomes:

S = 2*7*a + 2*7*4 + 2*a*4

simplify:

S = 14*a + 56 + 8*a

combine like terms:

S = 22*a + 56

-----

answer is:

S = 22*a + 56 (equation 2)

-----

to prove, substitute any value for a in equation 2:

let a = 15

S = 22*a + 56 (equation 2)

S = 22*15 + 56

S = 330 + 56

S = 386

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since a = 15, then W = 15 because W = a

go back to equation 1 and substitute 15 for W:

S = 2*L*W + 2*L*H + 2*W*H (equation 1)

where:

L = length

W = width

H = height

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you have:

L = 7

W = 15

H = 4

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equation 1 becomes:

S = 2*7*15 + 2*7*4 + 2*15*4

perform indicated operations:

S = 210 + 56 + 120

S = 386

-----

surface area is the same using both equations so:

equations are good.

formula for surface area of right rectangle in terms of a is:

S = 22*a + 56

-----

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Answer:

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