U^2 - u -30
Hope it helps.
Answer: {0, 1, 2}
<u>Step-by-step explanation:</u>
| 5 - 5x | < 10
The inside of the absolute value can be negative or positive, so we need to solve for both possibilities:
-(5 - 5x) < 10 +(5 - 5x) < 10
<em> Note: remember to swap the sign when dividing by a negative</em>
5 - 5x > -10 5 - 5x < 10
<em> </em> -5x > -15 -5x < 5
x < 3 x > -1
-1 < x < 3
Graph: -1 o·---------------o 3
The integers BETWEEN AND NOT INCLUDING -1 and 3 are: {0, 1, and 2}