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2 years ago

Mallory took out a loan for $1500. She paid the loan back in 1 year with 7% simple interest. How much did Mallory pay in total?

Mathematics

1 answer:

romanna [79]2 years ago

6 0

Answer:

$1605

Step-by-step explanation:

Because this is simple interest, you can convert the 7% into a decimal

Because she payed an EXTRA 7% she payed 107% total

107% is the equivalent to 1.07

By multiplying 1500 x 1.07 = 1605

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A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more pe

Molodets [167]

Answer:

T1(n) = 25n +119.50 where n belongs to $1 \leq n$ .

T2(n) = 20n + 59 where n belongs to $50\leq n$ .

Step-by-step explanation:

We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.

Let the number of person going for this restaurant be "n"

For normal day, we are given

catering service = $25 per person

service charge = $119.50

Let the total cost of the restaurant be T

Cost for this case will be T1

T1(n) = 25n +119.50 where n belongs to $1 \leq n$

similarly for the case when 50 or more than that goes to this restaurant for party.

cost after discount

Catering service = $20.00 per person

service charge = $59.00

now the cost of this case will be T2

T2(n) = 20n + 59 where n belongs to $50\leq n$ .

Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.

7 0

3 years ago

the equation shows the radius of the algae,f(d), in mm,after d days: f(d)=7(1.06)^d the radius of the algae was approximately 13

Andrei [34K]

Answer:

$\begin{gathered} A)\text{ }Domain:\text{ \lparen0,11\rparen} \\ B)\text{ the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.} \\ C)\text{ rate of change= 0.64. This means that on average the algae grows 0.64mm per day.} \end{gathered}$

Step-by-step explanation:

If the radius of the algae was approximately 13.29 mm, substitute f(d)=13.29 and solve for d to determine the domain:

$\begin{gathered} 13.29=7\left(1.06\right)^d \\ \frac{13.29}{7}=1.06^d \\ d=\frac{\text{ log\lparen13.29/7\rparen}}{\text{ log\lparen1.06\rparen}} \\ d=11 \\ \text{ Then, the domain:} \\ (0,11) \end{gathered}$

B. The y-intercept is obtained when d=0, hence;

$\begin{gathered} d=0 \\ f(0)=7(1.06)^0 \\ f(0)=7 \end{gathered}$

Therefore, the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.

C. Now, to determine the rate of change of a function, use the following equation:

$\text{ rate of change=}\frac{change\text{ over y}}{change\text{ over x}}$

Then, determine the value of f(4):

$\begin{gathered} f(4)=7(1.06)^4 \\ f(4)=8.83 \end{gathered}$

Hence, the rate of change on that interval of the function:

$\begin{gathered} \text{ rate of change=}\frac{13.29-8.83}{11-4} \\ \text{ rate of change=0.64 } \end{gathered}$

This means that on average the algae grows 0.64mm per day.

8 0

1 year ago

1.4 in standard form

lbvjy [14]

14

Step by step explanation

5 0

3 years ago

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ivann1987 [24]

The domain and simplified terms are marked below

7 0

3 years ago

Two 1.60cm×1.60cm plates that form a parallel-plate capacitor are charged to ± 0.711nC . What is the potential difference across

lina2011 [118]

The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V

7 0

3 years ago

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