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max2010maxim [7]
3 years ago
8

For a quadratic equation where: 2++=0

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

Solutions will be unreal

Step-by-step explanation:

Given the quadratic equation ax^2+bx+c

The discriminant of the function determines its nature of its root

Discriminant D = b^2-4ac

If D <0, it shows that the roots of the equation will be a complex value. since D is less than 0 and the square root of a negative number does not exist. Hence, the solutions will be unreal

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I need help plz <br> State the coordinates of the point.
Arisa [49]

Answer:

(-5,8)

Step-by-step explanation:

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5 0
3 years ago
This is converting to polar form, I need help and the answer too.
Mila [183]

Answer:

2 cis (7/6 pi)

Step-by-step explanation:

r = sqrt( a^2 + b^2)

r = sqrt (-sqrt(3) )^2 + (-1)^2)

   = sqrt(3 +1)

    = sqrt(4)

    = 2

theta  = arctan (b/a)

theta = arctan (-1/-sqrt(3))

theta = 30

but this is in the third quardrant  -a and -b

so add 180

theta = 210 degrees

convert this to radians

210 * pi/180 = 210/180 * pi = 21/18 * pi = 7/6 * pi


r cis (theta)

2 cis (7/6 pi)

7 0
3 years ago
Question 1) Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
USPshnik [31]

Question 1)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(G(x)) = 3(2x - 3)^2 + 1

F(G(x)) =3(4x^2 - 12x + 9) + 1

F(G(x)) = 12x^2 - 36x + 27 + 1

F(G(x)) =12x^2 - 36x + 28

Question 2)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

H -1 (x) = x (inverse)

8 0
3 years ago
1-1=............... HELP!!!!!!!!!!!!!!!!!!
Verizon [17]
1-1=0 lol how do u not know this ???
7 0
3 years ago
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