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3 years ago

Write the following expression in simplified radical form. 5th root (64x to the 7th power w to the 5th power)

1 answer:

3 0

The given expression is:

$\sqrt[5]{64 x^{7} w^{5} }$

The expression can be simplified as follows:

$\sqrt[5]{64 x^{7} w^{5} } \\ \\ 
= \sqrt[5]{(2)^{6} x^{7} w^{5} } \\ \\ 
= \sqrt[5]{(2)^{5}*2* x^{5}* x^{2} * w^{5} } \\ \\ 
= \sqrt[5]{ (2^{5} x^{5} w^{5} )*2 x^{2} } \\ \\ 
= \sqrt[5]{(2xw)^{5}*2 x^{2} } \\ \\ 
=2xw* \sqrt[5]{2x^{2} } 
$

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Using a number line what is the equivalent fraction to 1/4

AURORKA [14]

Step-by-step explanation:

For example, 1/2 and 2/4 are equivalent fractions. If you simplify 2/4 by dividing both the numerator and denominator by 2, you'll get 1/2, the same as the other one. Remember, our number line is a line with evenly spaced tick marks that show us our numbers.

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3 years ago

Work out the value of 4^0 x 16^0

NNADVOKAT [17]

Answer:

Step-by-step explanation:

Anything to the power of 0 is 1. So,

1 x 1 = 1

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2 years ago

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2(4x - 3) 2-3(3x) + 5x

SashulF [63]

Answer:

12x-12

Step-by-step explanation:

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3 years ago

A company that offers tubing trips down a river rents tubes for a person to use for $20 and “cooler” tubes to carry food and wat

Licemer1 [7]

Answer:

The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water

Explanation:

The rents for tubes for a person to use = $20

The rents for “cooler” tubes to carry food and water = $12.50.

The rent for a total of 15 tubes = $270

11 tubes whose rent cost $20 = $11 \times 20$

= 220

4 “cooler” tubes rent cost $12.50 = $4 \times 12.5$

= 50

Therefore for 15 tubes = 11 +4= 15

cost = 220 + 50

=270

The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water

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3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

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2 years ago