Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
7212960
Step-by-step explanation:
You have to round up since the number in the ones place is a 5.
Answer:
its 80 on edg
Step-by-step explanation:
The answer is -4.
i hope it helps you!
Answer:
8
Step-by-step explanation:
1 2 3 4 5 6 7 8 quick math