You just need to plug those expressions inside the formula: it doesn't matter if they're expressions involving a variable instead of plain numbers: the formula becomes

$V = \pi (x+8)^2(2x+3)$

If you want, you can simplify it by expanding the square and then multiply the two parenthesis:

$V = \pi (x^2+16x+64)(2x+3) = \pi (2 x^3 + 35 x^2 + 176 x + 192)$

6 0

2 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

wolverine [178]

.............................

4 0

2 years ago

Read 2 more answers

What is the inequality shown in the graph

rodikova [14]

It must be ≤ instead of ≥.

y ≤ - 3·x + 4

3 0

2 years ago