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Sauron [17]
3 years ago
11

Name a real number that is an irrational number between 0 and 1

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
6 0
Square roots that are not perfect squares are irrational.

An example could be √0.5 which equals 0.7071067811...
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5, –20, 80, <br><br> The geometric sequence?
leonid [27]

Step-by-step explanation:

This sequence is that you should multiply the number by 4 and one number should be positive the other should be negative so

5 -20 80 -320 1280

5 0
3 years ago
Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexic
erica [24]

The amount of dollars that Mr. Levant would exchange for 100 pesos on his return is <u>$9</u>.

<h3>What is an exchange rate?</h3>

An exchange rate is a rate that is used to convert one nation's currency to another.

The exchange rate is based on the purchasing power of each nation's currency.

<h3>Data and Calculations:</h3>

Dollars before traveling to Mexico = $270

Value of Mexican pesos received for $270 = 3,000 pesos

Exchange rate = $1 = 11.11 pesos (3,000/$270)

Amount of pesos left after the trip = 100 pesos

Value of 100 pesos in dollars = <u>$9</u> (100/$11.11)

Thus, the amount of dollars that Mr. Levant would exchange for 100 pesos on his return is <u>$9</u>.

Learn more about exchange rates at brainly.com/question/2202418

#SPJ1

4 0
1 year ago
Is (3,9) a solution of the system
Verdich [7]
Yes it because any function can be a solution to any certain number of different systems
6 0
2 years ago
Sin5A/SinA-cos5A/cosA=4cos2A​
irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

\frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ LHS = \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}   \\  \\  =  \frac{ \sin5A \:\cos A -  \cos5A \:  \sin A}{\sin A \:\cos A }  \\  \\  =  \frac{ \sin(5A -A )}{\sin A \:\cos A}  \\  \\ =  \frac{ \sin 4A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =4\cos 2A \\  \\  = RHS \\  \\ thus \\  \\  \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ hence \: proved

5 0
3 years ago
Which is the value of this expression when m=3 and n=-5? (6m^-1 n^0)^-3
iragen [17]

Answer:

The answer is C.

Step-by-step explanation:

I would simplify the expression first.

Equation: (6m^-1)^-3

You can get rid of n^0 because that equals 1.

Any expression raised to the power of -1 equals its reciprocal.

Equation: (6/m)^-3

Equation: (m/6)^3

Final Equation: m^3/216

Now, plug in 3.

(3)^3/216.

27/216 = 1/8

Hope this helps!

6 0
3 years ago
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