Ask question

Ask question

All categories

3 years ago

8

A plane, initially traveling 150 mi./hr. 100 east of north, suddenly enters a region where the wind is blowing at 50 mi./hr. fro

m the southwest.
What is the plane’s resultant direction?

1 answer:

Leona [35]3 years ago

5 0

Answer:

the Velocity of the plane is 100 mi/hr along the northeast direction

Step-by-step explanation:

According to the Question,

Given That, the Initial velocity of the plane is 150 mi/hr along the east north direction and the wind is blowing at 50 mi/hr along the southwest direction

since the velocity of wind and plane is exactly opposite

the relative velocity of the plane with respect to the wind is given by

$V_{r} = V_{p} -V_{w}$ , where $V_{p}$ is the velocity of plane = 150mi/hr and $V_{w}$ = velocity of wind = 50 mi/hr

Therefore, Relative Velocity = 150-50 ⇒ 100mi/hr along northeast direction

Thus, the velocity of the plane is 100 mi/hr along the northeast direction

You might be interested in

In the cafeteria there are 283 bananas left and 7 classes who still need to eat if each class shares the bananas equally how man

romanna [79]

Well we don't know the total of students so we divide 283 by 7.Which equals approximately to 41.

5 0

3 years ago

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

$AB=\sqrt{100}$

$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0

3 years ago

Select the correct answer

Kitty [74]

Answer:

(4,-7)

Step-by-step explanation:

-w=(5,-3)

-z=(-1,-4)

so -w-z=(5-1,-3-4)

4 0

3 years ago

Mr. Abaya goy P700,000 loan for the expansion of his business payable monthly in 4years. How much os the monthly amortization if

Vaselesa [24]

The monthly amortization is P23,511.63

<h2>Compound interest</h2>

The formula for calculating the compound interest is expressed as:

$A = P(1+r/n)^t$

whrere:

P is the principal = P700,000
r is the rate = 12% = 0.12
t is the time = 4 years
n = 12

Substitute the parameters

$A = 700000(1+0.12/12)^{4(12)}\\
A = 700,000(1.01)^{48}\\
A =1,128,558.25$

Calculate the monthly payment:

Monthly payment = $\frac{1,128,558.25}{48} =23,511.63$

Hence the monthly amortization is P23,511.63

Learn more on compound interest here: brainly.com/question/24924853

8 0

2 years ago

Complete the equation of the graphed linear function. Write the slope in decimal form.

erma4kov [3.2K]

Every straight line graph has an equation in the same form:

   y = (slope of the line) x + (y-intercept) .

-- The slope of the line is

   (how far it goes UP, going left to right between any 2 points)
divided by
   (how far it goes left to right between the same 2 points) .

The line on this graph has a slope of + 1/2 .

-- The y-intercept is the point where the line crosses the y-axis.
The line on this graph crosses the y-axis at -1 .

   y = (slope of the line) x + (y-intercept) .

   y = ( 0.5 ) x ( - 1 ) .

6 0

3 years ago

Read 2 more answers