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3241004551 [841]

2 years ago

14

Please help![3 x 2⁵ - 13 x (-2)] + 2³ (-2² +3²) - 3 Give your answer in simplest form.

2 answers:

Igoryamba2 years ago

8 0

Answer:

[3×2⁵+13×2]+2³(-2²+3²)-3=

[3×32+26]+2³(-4+9)-3=

[96+26]+2³(5)-3=

122+40-3

162-3=

159...

note:-a×(-b)=+ab

Vlad1618 [11]2 years ago

6 0

Answer:

122x + 37

Step-by-step explanation:

hope this helps u

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Diano4ka-milaya [45]

Let y be the temperature
Let m be the rate of temperature drop in degrees per hour
Let x be the number of hours elapsed since 8PM
The initial temperature (at x = 0) is 0
y = mx
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3 years ago

Lola plans to publish a magazine. She cannot publish unless she sells at least 100 subscriptions. Each subscription costs $20. T

dedylja [7]

Answer:

R(s) $\geq 2000$ ,

Step-by-step explanation:

The function R(s) = 20s

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Hence, is the domain of R(s) in this context

R(s) $\geq 2000$

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3 years ago

Is 8m-4m+4m and 8m equivalent?

marta [7]

Answer:

16

Step-by-step explanation:

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3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

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3 years ago