Answer:
6.
Step-by-step explanation:
This is [p(2+h)) - p(2) ] / ((2 + h - 2)
= [ 6(2) + h) + 7 - (6(2) + 7)] / h
= ( 12 + 6h + 7 - 12 - 7) / h
= 6h / h
= 6.
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Add them all up and if they add up to 180 then your side lengths are good
That I can not understand it looks weird.
We can use the Pythagorean theorem to solve for the perimeter of the kite.
a² + b² = c²
3² + 4² = UV²
9 + 16 = UV²
25 = UV²
√25 = √UV²
5 = UV
In the kite, adjacent sides are the same so UV = VW
3² + 9² = UX²
9 + 81 = UX²
90 = UX²
√90 = √UX²
9.49 ≈ UX or 3√10 ≈ UX
Now, add to find the perimeter.
5 + 5 + 9.49 + 9.49 or 5 + 5 + 3√10 + 3√10
28.98 or 10 + 6√10
Therefore, the perimeter is approximately 28.98 or 10 + 6√10
Best of Luck!
