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never [62]
2 years ago
9

Help me omg omg omg omg omg

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
5 0

Answer:

= -1.2 + 3.28d

Step-by-step explanation:

0.4 * -3 + 0.4 * 8.2d

= -1.2 + 3.28d

You might be interested in
A chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium to obtain a 70-milliliter mixture.Write th
Verdich [7]

Answer:

S(x)=-0.4x+42

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.

Step-by-step explanation:

It is given that a chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium-iodine to obtain a 70-milliliter mixture.

Let x be the number of milliliters of the 20% sodium-iodine.

Number of milliliters of the 60% sodium-iodine = 70-x

The amount of sodium iodine in the mixture is 20% of x and 60% of (70-x).

S(x)=0.20x+0.60(70-x)

S(x)=0.2x+42-0.6x

S(x)=-0.4x+42

Therefore,the required function is S(x)=-0.4x+42.

Substitute x=50 in the above equation.

S(50)=-0.4(50)+42

S(50)=22

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.

4 0
4 years ago
(Recall: 2.20 Ib. ~ 1 kg. ) Ib. ~ 14 kg.)
4vir4ik [10]
Since 2.20 lb is equal to 1 kg then 14 kg is equal to 30.8 lb
6 0
4 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
4 years ago
Homer's annual salary is $74,308. If he works all 52 weeks a year, how much is he paid each week?
ryzh [129]

Answer:

Step-by-step explanation:

You need to divide 74308 divided by 52 which equals 1429.

8 0
4 years ago
Help please would greatly appreciate it
Yakvenalex [24]

Answer:

It is 5:15

Step-by-step explanation:

3 0
3 years ago
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