Question

A chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium to obtain a 70-milliliter mixture.Write the amount of sodium iodine in the mixture,S,in milliliters, as a function of the number of milliliters of the 20% solution used,x.Then find and interpret S(50)

Answer 1

Answer:

$S(x)=-0.4x+42$

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.

Step-by-step explanation:

It is given that a chemist working on a flu vaccine needs to mix a 20% sodium-iodine with a 60% sodium-iodine to obtain a 70-milliliter mixture.

Let x be the number of milliliters of the 20% sodium-iodine.

Number of milliliters of the 60% sodium-iodine = 70-x

The amount of sodium iodine in the mixture is 20% of x and 60% of (70-x).

$S(x)=0.20x+0.60(70-x)$

$S(x)=0.2x+42-0.6x$

$S(x)=-0.4x+42$

Therefore,the required function is $S(x)=-0.4x+42$.

Substitute x=50 in the above equation.

$S(50)=-0.4(50)+42$

$S(50)=22$

The value of S(50) is 22 in means the amount of sodium iodine in the mixture is 22 when 50 milliliters of the 20% solution used.