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valkas [14]
2 years ago
6

Select the correct answer. A linear function on a coordinate plane passes through (minus 3, 2), (0, 4), and (3, 6) Which equatio

n describes the line graphed above? A. B. C. D.
Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0

Answer:

I don't see the equation options.  See below for a predicted equation.

y= (2/3)x + 4

Step-by-step explanation:

The points are (-3,2), (0,4), and (3,6).  I will assume they lie in a straight line.

Find an equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).

m, the slope, is also known as the "Rise/Run."

Pick any two points.  I'll use (0,4) and 3,6)

Rise = (6-4) = 2

Run  = (3-0) = 3

Slope = 2/3

The equation becomes y = (2/3)x + b

B is easy in this case.  Point (0,4) tells us that y = 4 when x = 0 (the definition of b).

The equation is y= (2/3)x + 4

See the attached graph.

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Answer:

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Step-by-step explanation:

Using this table, the tax is ...

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<em>Additional comment</em>

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3 years ago
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-Dominant- [34]

Answer:

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Write a polynomial function of least degree with integral coefficients that have the given zeros. 4,-1,6 f(x)=x^3-9x^2+14x+24
AlladinOne [14]

Answer:

see explanation

Step-by-step explanation:

Given the zeros of a polynomial, say x = a, x = b, x = c

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here x = 4, x = - 1, x = 6, hence

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f(x) = a(x - 4)(x + 1)(x - 6) ← a is a multiplier

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Answer:

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Step-by-step explanation:

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