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Vladimir [108]
3 years ago
6

Let x = -6 and b = 5 solve: x/3 +b^2

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

23

Step-by-step explanation:

pls give brainliest plzzzzzz

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Whats 9 times 9 plz tell me
anyanavicka [17]
Your answer is 81 because 9 times 9 is 81
8 0
3 years ago
Flve tickets to a carnlval cost $45. How much would seven<br> tickets cost?
Alecsey [184]

Answer:

$63

Step-by-step explanation:

In order to solve this problem, we need to find the unit price, which is the price per 1 ticket in this case. To find this, we need to divide $45 by 5 because each ticket is the same amount: $45 / 5 = $9. So each ticket is $9.

Now, we need to find how much 7 tickets would cost. To do this, multiply the $9 / ticket by 7 tickets: $9 * 7 = $63.

This, 7 tickets would cost $63.

Hope this helps! God Bless u!!!

5 0
3 years ago
Read 2 more answers
What is the value of the expression shown below
kaheart [24]

value of the expression \frac{1.6(10^{5})}{0.2(10^{2})} or   1.6(10^{5}) over 0.2(10^{2})  is 8000 (8 \times 10 ^3).

<u>Step-by-step explanation:</u>

Here we have , to find the value of the expression shown below  1.6 x 10 to the 5th power over 0.2 x 10 to the 2nd power i.e. 1.6(10^{5}) over 0.2(10^{2}) :

⇒  1.6(10^{5}) over 0.2(10^{2})

⇒ \frac{1.6(10^{5})}{0.2(10^{2})}

multiply and divide by 10 to remove decimals, so we get

⇒ \frac{16(10^{5})}{2(10^{2})}

⇒ \frac{8(2)(10^{5})}{2(10^{2})}

⇒ 8\frac{(10^{5})}{(10^{2})}

⇒ 8(10^{(5-2)})

⇒ 8(10^{3})

⇒ 8(1000)

⇒ 8000

Therefore, value of the expression \frac{1.6(10^{5})}{0.2(10^{2})} or   1.6(10^{5}) over 0.2(10^{2})  is 8000 (8 \times 10 ^3).

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4 years ago
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Write standard form twenty-five thousand, four hundred eight
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In standard form it is 25,408
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3 years ago
Math question helppp
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3 years ago
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