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Elden [556K]
1 year ago
10

Identify the graph of the inequality 2(2x-1)+7<13 or-2x + 5≤-10.

Mathematics
1 answer:
xxMikexx [17]1 year ago
5 0

Answer:

Step-by-step explanation:

2

(

2

x

−

1

)

+

7

<

13

Expand LHS

→

4

x

−

2

+

7

<

13

4

x

+

5

<

13

4

x

<

13

−

5

4

x

<

8

Divide through by

4

→

x

<

2

x

<

2

is represented on the real line by the interval

(

−

∞

,

2

)

This can be represented on the

x

y

−

plane by the area to the left of the vertical line

x

=

2

as graph below.

graph{2(2x-1)+7<13 [-10, 10, -5, 5]}

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3 years ago
Find the area D (1,3) F (-4,-3) E (4, -3)​
tresset_1 [31]

Answer:

Step-by-step explanation:

FE=4+4=8

Altitude=3+3=6

area=1/2×FE×6=1/2×8×6=24 sq. units.

or

area=1/2×

I 1   3|

|-4 -3|

| 4 -3|

|  1  3|

=1/2[(-3+12)+(12+12)+(12+3)]

=1/2[9+24+15]

=1/2[48]

=24 sq. units

7 0
2 years ago
If 16+4x is 10 more than 14, what is the value of 8x?
sattari [20]
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16 + 4x = 24.

4x = 24 - 16

4x = 8

x = 8 ÷ 4

x = 2

8x = 2 × 8

8x = 16

Final answer = 16.
3 0
3 years ago
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