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mars1129 [50]
3 years ago
9

The symbol^ => "means to the power of". The value of 3^2 + 2^3 10 points

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

17

Step-by-step explanation:

3^2 = 3*3 = 9

2^3 = 2*2*2 = 8

3^2 + 2^3 = 9 + 8 = 17

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What is the connection between the numbers A and B if A+B=0
Salsk061 [2.6K]

They're opposite numbers.

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Stephanie, Mike , and Howard gather blackberries for their grandmother. Stephanie picks 4 3/8 pounds, Mike picks 2.5 pounds, and
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Answer:B

Step-by-step explanation:

I don’t know

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Read 2 more answers
Solve each one variable equation.
uranmaximum [27]

Answer:

See below in bold.

Step-by-step explanation:

a.  |x| = 6

x = 6, -6.

b.  |x − 5| = 4

x - 5 = 4

x = 9.

x - 5 = -4

x = 1.

c. 2|x + 3| = −10

No solution because |x + 3| is an absolute value so is always positive.

8 0
3 years ago
Mike is reserving a room in frances, which uses euros. The room charge is 75 euros. If the conversion rate was 1 euro equals $1.
rusak2 [61]
To convert the euros into dollars simply multiply 75x1.29.
8 0
3 years ago
The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.
Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let \mu = <u><em>population mean score</em></u>

So, Null Hypothesis, H_0 : \mu \leq 29.5      {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, H_A : \mu > 29.5      {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean MCAT score = 32.2

            s = sample standard deviation = 4.2

            n = sample of students = 40

So, <u><em>the test statistics</em></u> =  \frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }  ~  t_3_9

                                    =  4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0
3 years ago
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