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mars1129 [50]
3 years ago
9

The symbol^ => "means to the power of". The value of 3^2 + 2^3 10 points

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

17

Step-by-step explanation:

3^2 = 3*3 = 9

2^3 = 2*2*2 = 8

3^2 + 2^3 = 9 + 8 = 17

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Cody bagged the plastic bottles after a recycling drive. He placed 15 bottles in the first bag, 90 bottles in the second bag, 36
stepan [7]

Answer: repeating sequence

Step-by-step explanation:

3 0
3 years ago
3/5 of the 30 students are boys how many students are girls
anygoal [31]

if 3/5 are boys

1- 3/5

5/5 -3/5 = 2/5  are girls

2/5 * 30 = 60/5 = 12

12 are girls

6 0
2 years ago
Read 2 more answers
El área de un rectángulo es 675cm2, si el largo es 3 veces. ¿Cuáles son las dimensiones del rectángulo?
Gala2k [10]
The answer is 15 cm. Hope I could be of help! ; )
7 0
3 years ago
Consider the continuous random variable x, which has a uniform distribution over the interval from 110 to 150. The probability t
Virty [35]

Answer:

The probability that x will take on a value between 120 and 125 is 0.14145

Step-by-step explanation:

For uniform distribution between a & b

Mean, xbar = (a + b)/2

Standard deviation, σ = √((b-a)²/12)

For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

Hope this Helps!!!

3 0
3 years ago
PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
Read 2 more answers
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