Answer:
The probability of getting a mottled offspring is 0%. There is no A2 allele involved in the cross.
Explanation:
<u>Available data</u>:
- The gene for petal color in a flower has incomplete dominance
- Two A1 alleles (A1A1) express black color
- Two A2 alleles (A2A2) express white color
- One of each allele (A1A2) express mottled color
In a cross between two black flowers, there is no allele A2, there are just two alleles A1. So, the cross is:
Parental) A1A1 x A1A1
Gametes) A1 A1 A1 A1
Punnet Square) A1 A1
A1 A1A1 A1A1
A1 A1A1 A1A1
F1 Phenotypes: 100% black flowers
F1 Genotype: 100% A1A1
There are 0% of probabilities of getting a mottled offspring.
The answer would be b.)AaBbCc<span>They because will receive one recessive </span>allele<span> from their father and one </span>dominant<span> allele from their mother at each </span>gene<span> locus.</span>
Answer:
Same phenotype but different genotype is possible due to presence of dominant allele
Explanation:
A person can have a dominant allele on both the homologous chromosomes while another person may have single dominant allele and a corresponding recessive allele.
