Solution: Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places 5 calls. what is the probability that none of them reaches a live person.

Answer: The given random experiment can be considered as binomial experiment with probability of success = 0.2 and number of trials = 5

Therefore, we have:

$n=5,p=0.2,q=(1-p)=1-0.2=0.8$

Let x be the number calls that reach to live person.

We have to find $P(x=0)$

Using the binomial probability distribution, we have:

$P(x=0)=\binom{5}{0}0.2^{0} (1-0.2)^{5-0}$

$=1 \times 1 \times 0.8^{5}$

$=0.3277$

Therefore, the probability that none of them reaches a live person is 0.3277

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2 years ago

2(4t-2)+t=16-t solution set is

ser-zykov [4K]

T=2 the solution set is t=2

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2 years ago

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