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Likurg_2 [28]
4 years ago
13

The compound inequality 8.00 ≤ x < 9.50 represents all values, x, for which college students are paid hourly as teacher assis

tants. What is another way of writing this compound inequality?
A. x ≤ 8.00 and x < 9.50
B. x ≤ 8.00 or x < 9.50
C. x ≥ 8.00 and x < 9.50
D. x ≥ 8.00 or x < 9.50
Mathematics
2 answers:
Svet_ta [14]4 years ago
10 0
<span>the answer is C. x ≥ 8.00 and x < 9.50
proof 
</span>x ≥ 8.00 is equivalent to 8.00 ≤ x,  and we have also <span>x < 9.50
so </span>x ≥ 8.00 and x < 9.50 or <span>8.00 ≤ x < 9.50</span>
Tresset [83]4 years ago
4 0

Answer:

The answer is C.

Step-by-step explanation:

Just did question and got it right in edgenuity :)

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A circle is increased to have a circumference that is 4 times larger than the original. Which of the following options best desc
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Thus when the radius is doubled, or in other words if radius mad 2 time the original radius, the area of circle will become 2^2 = 4 time the original area. The circumference will become 2 times the original circumference.

We can calculate exact area and circumference of a circle from its radius using the following equations:

Area of circle = (pi/4)*r^2

Circumference of circle = 2*pi*r

Where r is the radius of the circle.

I know this is a lot, sorry.
3 0
3 years ago
Bert has already read 5 pages, and he knows he can read 11 more pages during every additional hour he spends reading. In all, ho
lukranit [14]

Answer:

4 hours

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7 0
4 years ago
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What are the solutions to the quadratic equation (5y + 6)2 = 24?
lana [24]
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6 0
3 years ago
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Refer to the photo :D
OlgaM077 [116]

well, we know the ceiling is 6+2/3 high, and Eduardo has 4+1/2 yards only, how much more does he need, well, is simply their difference, let's firstly convert the mixed fractions to improper fractions and then subtract.

\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}} ~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{20}{3}-\cfrac{9}{2}\implies \stackrel{using ~~\stackrel{LCD}{6}}{\cfrac{(2\cdot 20)-(3\cdot 9)}{6}}\implies \cfrac{40-27}{6}\implies \cfrac{13}{6}\implies\blacktriangleright 2\frac{1}{6} \blacktriangleleft

4 0
3 years ago
I’m the triangle shown below what is the approximate value of x
Dafna1 [17]

Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides x,y and hypotenuse z:

x^2+y^2=z^2.

In our case

z=26

y=13

So we solve for x:

x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2}  =\boxed{22.52\: units.}

Which is choice B.

8 0
3 years ago
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