Step 3: Now multiply the values to get 14,918,904,000. That is almost 15 billion passwords.

1 answer:

7 0

The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600

<h3>How to determine the number of passwords</h3>

The given parameters are:

Password length = 8

Letters = 6

Numbers = 2

There are 26 letters and 10 digits.

Since the letters and the numbers can be repeated, then the number of passwords is:

Count = 26^6 * 10^2

Evaluate

Count = 30891577600

Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600

You might be interested in

Baseball player wants to hit a baseball over the fence the fence is 25 feet tall baseball players 52 feet away from the fence at

Igoryamba

Answer:

75 degree angle

heart if this helped :3

7 0

3 years ago

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so $\mu = 145, \sigma = 25$ .