I hope this helps, it’s a bit messy but yeahh
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
24 feet
Set up a ratio of object height to shadow length.
So x/32=6/8
8(4)=32 so 6(4) would be 24.
8 times (4 + 5 + 7) evaluate.
8 × (4 + 5 + 7)
<span>8 × (16)
</span>128
<span>8 times (4+5+7) is 128. </span>
C=2πr and x^2+y^2=r^2
r=4 because of the equation (16)^1/2 is 4
C=8π
