The answers are low concentrated (dilute) and high concentrated respectively.
As the low concentrated salt solution has a higher water potential than that of the high concentrated salt solution, water molecules will flow from the region of higher water potential to the region of lower water potential, thus from the dilute salt solution to the high concentrated salt solution. This is due to the movement called osmosis. Note that osmosis also requires water to flow through a differentially permeable membrane, which means the membrane can allow certain substances (not all) to go in or out. If the differentially permeable membrane is not present, the movement of water molecules may be regarded as diffusion.
Therefore, the answers for the blanks are low concentrated and high concentrated.
Sodium bicarbonate (or baking soda) will cause both exothermic and endothermic reactions when added to water. It becomes either unstable or stable carbonic acid, which will eventually become CO2. The reaction would be exothermic is when H2CO3 (Carbonic Acid unstable) is formed and endothermic is when CO2 is.
Two different atoms have nine protons each and the same mass. However, one is neutral while the other has a negative charge then the atomic structure of the both atom are of same element but one of them is electrically neutral and other has a stable electronic configuration
An atom is said to be neutral because it has an equal number of electron and proton in it and if two different atom have nine proton each and same the mass but one is neutral while the other has a negative charge and the mass of an atom is determined by the number of proton and neutron is present in its nucleus and since both the given atom have 9 proton and the same mass and they must also have the same number of neutron
This implies both the atom have the same nucleus but different charges so it can be concluded that they both the atom of the same element but one of them is electrically neutral and other has stable electronic configuration
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Answer: a) is the limiting reagent
b) 3.59 g
c) 11.6g
Explanation:
To calculate the moles :
According to stoichiometry :
a) 9 moles of require= 4 moles of
Thus 0.15 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
b) As 9 moles of give = 8 moles of
Thus 0.15 moles of give = of
Mass of
c) As 9 moles of give = 3 moles of
Thus 0.15 moles of give = of
Mass of