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2 years ago

Which missing item would complete this alpha decay reaction?

Chemistry

1 answer:

Darina [25.2K]2 years ago

8 0

Answer:

option c is correct answer.

during alpha decay mass of daughter atom is 4 unit less than its parent atom and its atomic number is 2 unit less than its parent atom.

$\sf so , \: ^4 _2 He \: atom \: is \: released .$

Therefore, option c is answer.

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Calculate the mass of 0.5dm3 of a 2g/dm3 solution of silver nitrate

cupoosta [38]

Answer:

5.6

Explanation:

Because of the gravity of the earth

6 0

3 years ago

Which of the following is NOT the same as 13.6 milliliters?

rjkz [21]

HI There!

Which of the following is NOT the same as 13.6 milliliters?- 0.0136 dkL
- 0.0136 L
- 0.136 dL

Answer:<span>0.0136 dkL</span>

4 0

3 years ago

Suppose that the saturation magnetization Mmax of the ferromagnetic metal nickel is 4.41 × 105 A/m. Calculate the magnetic momen

Lady bird [3.3K]

Answer : The magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

Explanation :

Formula used :

$M_{max}=(\frac{N}{V})\times \mu$

where,

$M_{max}$ = saturation magnetization = $4.41\times 10^5A/m$

N = Avogadro's number = $6.022\times 10^{23}atoms/mol$

V = volume of nickel atom

$\mu$ = magnetic moment

First we have to calculate the volume of nickel atom.

$Density=\frac{Mass}{Volume}$

$8.90g/cm^3=\frac{58.71g/mol}{Volume}$

$Volume=\frac{58.71g}{8.90g/cm^3}$

$Volume=6.59cm^3=6.59\times (100)^3m^3$

Now we have to calculate the magnetic moment of a single nickel atom.

$M_{max}=(\frac{N}{V})\times \mu$

$4.41\times 10^5=(\frac{(6.022\times 10^{23})}{6.59})\times (100^3)\times \mu$

$\mu=4.82\times 10^{-24}Am^2$

Therefore, the magnetic moment of a single nickel atom is $4.82\times 10^{-24}Am^2$

7 0

3 years ago

Write the given numbers in standard notation, maintaining the same number of significant figures.

svetlana [45]

Answer:

0.0761.

0.0059.

Explanation:

Hello!

In this case, since the writing of numbers in standard notation given the scientific notation requires adding zeros to the left of the first nonzero digit, for the first number, we need to add two zeros as seven is the third digit position:

0.0761.

Next, we need to add three zeros as 5 would be the fourth digit:

0.0059.

Best regards!

4 0

3 years ago

Mr. Wells told his students that the Water cycle DOES have a clear beginning and a clear end. Mrs. Meador disagrees with him and

mixas84 [53]

Mrs Meador, because the water cycle is continuous and therefore has no clear end or beginning

4 0

3 years ago